Pierwiastek kwadratowy

Pierwiastek kwadratowy

• \sqrt{25}=5; √25  =  5;  \sqrt{0,01}=0,1; √0, 01  =  0, 1;  \sqrt{\frac{1}{4}}=\frac{1}{2} √14  =  12
  
  \sqrt{a}=b √a  =  b , gdy \left.\mleft.b\mright.\right?^{\mleft.2\mright.}=a b2  =  a dla b\left.\right.{{\fontfamily{ams}\geqslant }}\left.\right.0 b ⩾ 0 , a\left.\right.{{\fontfamily{ams}\geqslant \left.\right.}}0 a ⩾  0
  
  
• \left.\mleft.\left(\sqrt{31}\right)\mright.\right.^{\mleft.2\mright.}=31; (√31)2  =  31;  \left.\mleft.\left(\sqrt{2}\right)\mright.\right.^{\mleft.2\mright.}=2 (√2)2  =  2
  
  \left.\mleft.\left(\sqrt{a}\right)\mright.\right.^{\mleft.2\mright.}=a (√a)2  =  a  dla a\left.\right.{{\fontfamily{ams}\geqslant \left.\right.}}0 a ⩾  0
  
  
• \sqrt{\left.\mleft.\left(-2\right)\mright.\right.^{\mleft.2\mright.}}=\left|-2\right|=2; √(−2)2  =  ∣−2∣=  2;  \sqrt{\left.\mleft.2\mright.\right.^{\mleft.2\mright.}}=\left|2\right|=2 √22  =  ∣2∣=  2
  
  \sqrt{\left.\mleft.\left(a\right)\mright.\right.^{\mleft.2\mright.}}=\left|a\right| √(a)2  =  ∣a∣ dla dowolnego a a